Optimal. Leaf size=639 \[ -\frac{2 b^2 f (e+f x) \text{PolyLog}\left (2,\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d^2 \sqrt{a^2-b^2}}+\frac{2 b^2 f (e+f x) \text{PolyLog}\left (2,\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d^2 \sqrt{a^2-b^2}}-\frac{2 i b^2 f^2 \text{PolyLog}\left (3,\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d^3 \sqrt{a^2-b^2}}+\frac{2 i b^2 f^2 \text{PolyLog}\left (3,\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d^3 \sqrt{a^2-b^2}}-\frac{2 i b f (e+f x) \text{PolyLog}\left (2,-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{PolyLog}\left (2,e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 b f^2 \text{PolyLog}\left (3,-e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 b f^2 \text{PolyLog}\left (3,e^{i (c+d x)}\right )}{a^2 d^3}-\frac{i f^2 \text{PolyLog}\left (2,e^{2 i (c+d x)}\right )}{a d^3}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d \sqrt{a^2-b^2}}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d \sqrt{a^2-b^2}}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i (e+f x)^2}{a d} \]
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Rubi [A] time = 1.20559, antiderivative size = 639, normalized size of antiderivative = 1., number of steps used = 24, number of rules used = 12, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.429, Rules used = {4535, 4184, 3717, 2190, 2279, 2391, 4183, 2531, 2282, 6589, 3323, 2264} \[ -\frac{2 b^2 f (e+f x) \text{PolyLog}\left (2,\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d^2 \sqrt{a^2-b^2}}+\frac{2 b^2 f (e+f x) \text{PolyLog}\left (2,\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d^2 \sqrt{a^2-b^2}}-\frac{2 i b^2 f^2 \text{PolyLog}\left (3,\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d^3 \sqrt{a^2-b^2}}+\frac{2 i b^2 f^2 \text{PolyLog}\left (3,\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d^3 \sqrt{a^2-b^2}}-\frac{2 i b f (e+f x) \text{PolyLog}\left (2,-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{PolyLog}\left (2,e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 b f^2 \text{PolyLog}\left (3,-e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 b f^2 \text{PolyLog}\left (3,e^{i (c+d x)}\right )}{a^2 d^3}-\frac{i f^2 \text{PolyLog}\left (2,e^{2 i (c+d x)}\right )}{a d^3}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 d \sqrt{a^2-b^2}}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{\sqrt{a^2-b^2}+a}\right )}{a^2 d \sqrt{a^2-b^2}}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i (e+f x)^2}{a d} \]
Antiderivative was successfully verified.
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Rule 4535
Rule 4184
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 4183
Rule 2531
Rule 2282
Rule 6589
Rule 3323
Rule 2264
Rubi steps
\begin{align*} \int \frac{(e+f x)^2 \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac{\int (e+f x)^2 \csc ^2(c+d x) \, dx}{a}-\frac{b \int \frac{(e+f x)^2 \csc (c+d x)}{a+b \sin (c+d x)} \, dx}{a}\\ &=-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{b \int (e+f x)^2 \csc (c+d x) \, dx}{a^2}+\frac{b^2 \int \frac{(e+f x)^2}{a+b \sin (c+d x)} \, dx}{a^2}+\frac{(2 f) \int (e+f x) \cot (c+d x) \, dx}{a d}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}+\frac{\left (2 b^2\right ) \int \frac{e^{i (c+d x)} (e+f x)^2}{i b+2 a e^{i (c+d x)}-i b e^{2 i (c+d x)}} \, dx}{a^2}-\frac{(4 i f) \int \frac{e^{2 i (c+d x)} (e+f x)}{1-e^{2 i (c+d x)}} \, dx}{a d}+\frac{(2 b f) \int (e+f x) \log \left (1-e^{i (c+d x)}\right ) \, dx}{a^2 d}-\frac{(2 b f) \int (e+f x) \log \left (1+e^{i (c+d x)}\right ) \, dx}{a^2 d}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{2 i b f (e+f x) \text{Li}_2\left (-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{Li}_2\left (e^{i (c+d x)}\right )}{a^2 d^2}-\frac{\left (2 i b^3\right ) \int \frac{e^{i (c+d x)} (e+f x)^2}{2 a-2 \sqrt{a^2-b^2}-2 i b e^{i (c+d x)}} \, dx}{a^2 \sqrt{a^2-b^2}}+\frac{\left (2 i b^3\right ) \int \frac{e^{i (c+d x)} (e+f x)^2}{2 a+2 \sqrt{a^2-b^2}-2 i b e^{i (c+d x)}} \, dx}{a^2 \sqrt{a^2-b^2}}-\frac{\left (2 f^2\right ) \int \log \left (1-e^{2 i (c+d x)}\right ) \, dx}{a d^2}+\frac{\left (2 i b f^2\right ) \int \text{Li}_2\left (-e^{i (c+d x)}\right ) \, dx}{a^2 d^2}-\frac{\left (2 i b f^2\right ) \int \text{Li}_2\left (e^{i (c+d x)}\right ) \, dx}{a^2 d^2}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{2 i b f (e+f x) \text{Li}_2\left (-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{Li}_2\left (e^{i (c+d x)}\right )}{a^2 d^2}+\frac{\left (2 i b^2 f\right ) \int (e+f x) \log \left (1-\frac{2 i b e^{i (c+d x)}}{2 a-2 \sqrt{a^2-b^2}}\right ) \, dx}{a^2 \sqrt{a^2-b^2} d}-\frac{\left (2 i b^2 f\right ) \int (e+f x) \log \left (1-\frac{2 i b e^{i (c+d x)}}{2 a+2 \sqrt{a^2-b^2}}\right ) \, dx}{a^2 \sqrt{a^2-b^2} d}+\frac{\left (i f^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i (c+d x)}\right )}{a d^3}+\frac{\left (2 b f^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a^2 d^3}-\frac{\left (2 b f^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a^2 d^3}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{2 i b f (e+f x) \text{Li}_2\left (-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{Li}_2\left (e^{i (c+d x)}\right )}{a^2 d^2}-\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}+\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}-\frac{i f^2 \text{Li}_2\left (e^{2 i (c+d x)}\right )}{a d^3}+\frac{2 b f^2 \text{Li}_3\left (-e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 b f^2 \text{Li}_3\left (e^{i (c+d x)}\right )}{a^2 d^3}+\frac{\left (2 b^2 f^2\right ) \int \text{Li}_2\left (\frac{2 i b e^{i (c+d x)}}{2 a-2 \sqrt{a^2-b^2}}\right ) \, dx}{a^2 \sqrt{a^2-b^2} d^2}-\frac{\left (2 b^2 f^2\right ) \int \text{Li}_2\left (\frac{2 i b e^{i (c+d x)}}{2 a+2 \sqrt{a^2-b^2}}\right ) \, dx}{a^2 \sqrt{a^2-b^2} d^2}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{2 i b f (e+f x) \text{Li}_2\left (-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{Li}_2\left (e^{i (c+d x)}\right )}{a^2 d^2}-\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}+\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}-\frac{i f^2 \text{Li}_2\left (e^{2 i (c+d x)}\right )}{a d^3}+\frac{2 b f^2 \text{Li}_3\left (-e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 b f^2 \text{Li}_3\left (e^{i (c+d x)}\right )}{a^2 d^3}-\frac{\left (2 i b^2 f^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2\left (\frac{i b x}{a-\sqrt{a^2-b^2}}\right )}{x} \, dx,x,e^{i (c+d x)}\right )}{a^2 \sqrt{a^2-b^2} d^3}+\frac{\left (2 i b^2 f^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2\left (\frac{i b x}{a+\sqrt{a^2-b^2}}\right )}{x} \, dx,x,e^{i (c+d x)}\right )}{a^2 \sqrt{a^2-b^2} d^3}\\ &=-\frac{i (e+f x)^2}{a d}+\frac{2 b (e+f x)^2 \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a^2 d}-\frac{(e+f x)^2 \cot (c+d x)}{a d}-\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{i b^2 (e+f x)^2 \log \left (1-\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d}+\frac{2 f (e+f x) \log \left (1-e^{2 i (c+d x)}\right )}{a d^2}-\frac{2 i b f (e+f x) \text{Li}_2\left (-e^{i (c+d x)}\right )}{a^2 d^2}+\frac{2 i b f (e+f x) \text{Li}_2\left (e^{i (c+d x)}\right )}{a^2 d^2}-\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}+\frac{2 b^2 f (e+f x) \text{Li}_2\left (\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^2}-\frac{i f^2 \text{Li}_2\left (e^{2 i (c+d x)}\right )}{a d^3}+\frac{2 b f^2 \text{Li}_3\left (-e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 b f^2 \text{Li}_3\left (e^{i (c+d x)}\right )}{a^2 d^3}-\frac{2 i b^2 f^2 \text{Li}_3\left (\frac{i b e^{i (c+d x)}}{a-\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^3}+\frac{2 i b^2 f^2 \text{Li}_3\left (\frac{i b e^{i (c+d x)}}{a+\sqrt{a^2-b^2}}\right )}{a^2 \sqrt{a^2-b^2} d^3}\\ \end{align*}
Mathematica [A] time = 11.9213, size = 911, normalized size = 1.43 \[ \frac{i \left (-2 \sqrt{a^2-b^2} d f (e+f x) \text{PolyLog}\left (2,\frac{b e^{i (c+d x)}}{\sqrt{b^2-a^2}-i a}\right )+2 \sqrt{a^2-b^2} d f (e+f x) \text{PolyLog}\left (2,-\frac{b e^{i (c+d x)}}{i a+\sqrt{b^2-a^2}}\right )-i \left (\left (2 \sqrt{b^2-a^2} \tan ^{-1}\left (\frac{i a+b e^{i (c+d x)}}{\sqrt{a^2-b^2}}\right ) e^2+\sqrt{a^2-b^2} f x (2 e+f x) \left (\log \left (1-\frac{b e^{i (c+d x)}}{\sqrt{b^2-a^2}-i a}\right )-\log \left (\frac{e^{i (c+d x)} b}{i a+\sqrt{b^2-a^2}}+1\right )\right )\right ) d^2+2 \sqrt{a^2-b^2} f^2 \text{PolyLog}\left (3,\frac{b e^{i (c+d x)}}{\sqrt{b^2-a^2}-i a}\right )-2 \sqrt{a^2-b^2} f^2 \text{PolyLog}\left (3,-\frac{b e^{i (c+d x)}}{i a+\sqrt{b^2-a^2}}\right )\right )\right ) b^2}{a^2 \sqrt{-\left (a^2-b^2\right )^2} d^3}+\frac{-b d^2 x^2 \log \left (1-e^{-i (c+d x)}\right ) f^2+b d^2 x^2 \log \left (1+e^{-i (c+d x)}\right ) f^2+2 b \left (i d x \text{PolyLog}\left (2,-e^{-i (c+d x)}\right )+\text{PolyLog}\left (3,-e^{-i (c+d x)}\right )\right ) f^2-2 i b \left (d x \text{PolyLog}\left (2,e^{-i (c+d x)}\right )-i \text{PolyLog}\left (3,e^{-i (c+d x)}\right )\right ) f^2-2 d (b d e-a f) x \log \left (1-e^{-i (c+d x)}\right ) f+2 d (b d e+a f) x \log \left (1+e^{-i (c+d x)}\right ) f+2 i (b d e+a f) \text{PolyLog}\left (2,-e^{-i (c+d x)}\right ) f+2 i (a f-b d e) \text{PolyLog}\left (2,e^{-i (c+d x)}\right ) f-\frac{2 i a d^2 (e+f x)^2}{-1+e^{2 i c}}+i d e (b d e-2 a f) \left (d x+i \log \left (1-e^{i (c+d x)}\right )\right )+d e (b d e+2 a f) \left (\log \left (1+e^{i (c+d x)}\right )-i d x\right )}{a^2 d^3}+\frac{\csc \left (\frac{c}{2}\right ) \csc \left (\frac{c}{2}+\frac{d x}{2}\right ) \left (\sin \left (\frac{d x}{2}\right ) e^2+2 f x \sin \left (\frac{d x}{2}\right ) e+f^2 x^2 \sin \left (\frac{d x}{2}\right )\right )}{2 a d}+\frac{\sec \left (\frac{c}{2}\right ) \sec \left (\frac{c}{2}+\frac{d x}{2}\right ) \left (\sin \left (\frac{d x}{2}\right ) e^2+2 f x \sin \left (\frac{d x}{2}\right ) e+f^2 x^2 \sin \left (\frac{d x}{2}\right )\right )}{2 a d} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 2.214, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( fx+e \right ) ^{2} \left ( \csc \left ( dx+c \right ) \right ) ^{2}}{a+b\sin \left ( dx+c \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 4.9288, size = 6947, normalized size = 10.87 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e + f x\right )^{2} \csc ^{2}{\left (c + d x \right )}}{a + b \sin{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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